5v^2+18v+12=3

Solution for 5v^2+18v+12=3 equation:

5v^2+18v+12=3

We move all terms to the left:

5v^2+18v+12-(3)=0

We add all the numbers together, and all the variables

5v^2+18v+9=0

a = 5; b = 18; c = +9;
Δ = b2-4ac
Δ = 182-4·5·9
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-12}{2*5}=\frac{-30}{10}
=-3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+12}{2*5}=\frac{-6}{10}
=-3/5
$